Answer:
[tex]\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }[/tex]
[tex]\boxed { \frac{3}{5}y } \to \: \boxed {y - \frac{2}{5}y }[/tex]
Step-by-step explanation:
We need to simplify
[tex]y + \frac{2}{5}y[/tex]
We collect LCM to get;
[tex] \frac{5y + 2y}{5} = \frac{7y}{5} [/tex]
Therefore:
[tex] \boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }[/tex]
Also we need to simplify:
[tex]y - \frac{2}{5}y[/tex]
We collect LCM to get;
[tex]y - \frac{2}{5}y = \frac{5y - 2y}{5} = \frac{3}{5} y[/tex]
Therefore
[tex]\boxed { \frac{3}{5}y } \to \: \boxed {y - \frac{2}{5}y }[/tex]
