I am not sure how to even start this problem or how to write it in equation form.

let x,y,z be the 3 installments.
You will get the equations:
x+y+z = 76000
.08x + .06y + .09z = 5940
The second last sentence states:
.08x = 6*(0.6y)
which is just:
x = 4.5y
Substitute into our two equations to get:
5.5y +z = 76000
.42y + .09z = 5940
The first equation, solve for z:
z = 76000 - 5.5y
Substitute that into the second equation:
.42y +6840 - 0.495y = 5940
-0.075y = -900
y = 12000
Now back substitute our y-value back into our original equation to get:
x = 54000
z = 10000
Since x is our first installment, the answer is $54000.
Answer: first part = $54,000, second part = $12,000, third part = $10,000
Explanation:
Amount Invested Rate Interest
Part 1 x 0.08 0.08x
Part 2 y 0.06 0.06y
Part 3 z 0.09 0.09z
TOTAL 76,000 ****** 5,940
Interest:
0.08x + 0.06y + 0.09z = 5940
0.36y + 0.06y + 0.09(76,000 - 5.5y) = 5940
0.42y + 6840 - 0.495y = 5940
6840 - 0.075y = 5940
- 0.075y = -900
[tex]\frac{-0.075}{-0.075}y[/tex] = [tex]\frac{-900}{-0.075}[/tex]
y = 12,000
x = 4.5y
x = 4.5(12,000)
x = 54,000
Amount Invested Rate Interest
Part 1 54,000 0.08 0.08(54,000) = 4,320
Part 2 12,000 0.06 0.06(12,000) = 720
Part 3 10,000 0.09 0.09(10,000) = 900
TOTAL 76,000 ****** 5,940