Answer:
7.50 m
Step-by-step explanation:
The side lengths of the "special triangle" with angles 30°-60°-90° have the ratios 1 : √3 : 2. These ratios can be used to solve the problem.
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The parts of the tree of interest correspond to the long side and the hypotenuse of a 30-60-90 triangle.
In terms of the above ratio units, the fraction of tree height that is broken off is ...
[tex]\dfrac{\text{hypotenuse}}{\text{hypotenuse $+$ long side}}=\dfrac{2}{2+\sqrt{3}}\approx0.535898[/tex]
So, the length of the broken part of the tree is ...
0.535898 × 14 m ≈ 7.50 m
