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18-10-2017
Mathematics

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A cheetah can run 103 feet per second. A zebra can run x feet per second. Use the Distributive Property to write and simplify an expression for how much farther the cheetah can run in 10 seconds

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barnuts barnuts

27-10-2017

We are given that the rate of cheetah Rc is:

Rc = 103 ft / sec

And the rate of zebra Rz is:

Rz = x ft / sec

We are to find the distance between the two after 10 seconds, that is:

distance = (103 – x) 10

distance = 1030 – 10 x

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