Answer:
Pd(O2CCH3)2
Pd2C8H12O8
Explanation:
Given:
% Pd = 47.40
% O = 28.50
% C = 21.40
% H = 2.69
To determine:
Molecular formula of the compound containing Pd, O, C and H
Calculation:
Let the mass of the compound = 100g
Therefore based on the % compositions:
Mass of Pd = 47.40g
Mass of O = 28.50g
Mass of C = 21.40g
Mass of H = 2.69g
Atomic mass of Pd = 106.42 g/mol
Atomic mass of O = 15.99 g/mol
Atomic mass of C = 12.01 g/mol
Atomic mass of H = 1.00 g/mol
[tex]moles\ of\ Pd = \frac{47.40g}{106.42g/mol} =0.4454[/tex]
[tex]moles\ of\ O = \frac{28.50g}{15.99g/mol} =1.782[/tex]
[tex]moles\ of\ C = \frac{21.40g}{12.01g/mol} =1.782[/tex]
[tex]moles\ of\ H= \frac{2.69g}{1.00g/mol} =2.690[/tex]
Ratio:
[tex]Pd = \frac{0.4454}{0.4454} = 1.00\\\\O = \frac{1.782}{0.4454} = 4.00\\\\C = \frac{1.782}{0.4454} = 4.00\\\\H = \frac{2.690}{0.4454} = 6.039[/tex]
The empirical formula is : PdO4C4H6
Molecular formula = n(Empirical formula)
If n = 1
Molecular formula = PdO4C4H6 i.e. Pd(O2CCH3)2
If n= 2
Molecular formula = 2(PdO4C4H6)= Pd2O8C8H12
