I am confused about this question in trigonometry:

use AE and CE to find the angle
AE = 20, CE = 6
so the angle FOR CAE = tan^-1(6/20) = 16.7 degrees
to Find DF
a^2 = b^2 +c^2-2abcos(A)
a^2 = 10^2 + 14^2 -2(14)(10)cos(16.7)
a^2 = 30
sqrt((30)=5.47 rounded to 5.5
EF =
a^2 = b^2 +c^2-2abcos(A)
a^2 = 20^2 + 14^2 -2(14)(20)cos(16.7)
a^2 = 64
sqrt(64)=8