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the legs of a right triangle have lengths of 28 meters and 21 meters. the hypotenuse has a lenght of 5x meters. what is the value of x

Respuesta :

[tex]a=21 \ m , \ b=28 \ m , \ c=5x \ m \\ \\c^2 =a^2 + b^2\\ \\(5x)^2 =21^2 + 28^2\\ \\25x^2=441+784\\ \\25x^2=1225/:25\\ \\x^2=49\\ \\x=\sqrt{49}\\ \\x=7 \ m[/tex]

The value of x  of a triangle that has the legs of lengths 28 meters and 21

meters and the hypotenuse of 5x meters is 7

The triangle is a right angle triangle .

Using Pythagoras theorem, let's find the hypotenuse side and invariably the value of x

c² =a² + b²

(5x)² = 28² + 21²

25x² = 784 + 441

25x² = 1225

square root both sides

5x = √1225

5x = 35

divide both sides by 5

5x / 5 = 35 / 5

x = 7

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