A basket contains 11 apples, of which two are rotten. a sample of three apples is selected at random. in how many ways can two rotten apples be chosen?

the ways the two rotten apple be selected in taking 3 apples from the bag, can be solve using fundamental counting principles.
P = 2 x 1 x 9
P = 18 ways
the first digit is 2 because there are 2 rotten apples. then next is 1 because only 1 apples is now left after you pick the first rotten apple. then next is 9 because there no rotten apple left and 9 apples were left

Answer Link

abidemiokin abidemiokin · Answer 2 · 2021-11-03T14:12:47+01:00

The number of ways two rotten apples can be selected is 3 ways

The combination rule has to do with selection. If r objects are selected from a pool of n objects, the number of ways this can be done is expressed according to the formula:

[tex]nC_r=\frac{n!}{(n-r)!r!}\\[/tex]

According to the question, if a sample of three apples is selected at random where two apples are rotten, the number of ways these 2 apples can be chosen is expressed as:

[tex]3C_2=\frac{3!}{(3-2)!2!}\\3C_2=\frac{3}{2!}\\3C_2 =3ways[/tex]

This shows that the number of ways two rotten apples can be selected is 3 ways

Learn more here: https://brainly.com/question/6654189