ABC is a triangle and PQ is parallel to BC.
BC = 12.6 cm, PQ = 8.4cm and AQ = 7.2 cm.
Find AC.
(i know that parallel lines divide triangle sides proportionally, but can someone do a detailed step on AC)
The ratio of the sides of the two figures are in a constant ratio ie. BC/AC = PQ/AQ 12.6/AC = 8.4/7.2 Cross multiply 8.4AC =12.6x7.2 8.4AC = 90.72 Divide through by 8.4 AC= 10.8 cm
