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18-01-2017
Chemistry

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4. A big league hitter attacks a fastball! The ball has a mass of 0.16 kg. It is pitched at 38 m/s. After the player hits the ball, it is now traveling 44 m/s in the opposite direction. The impact lasted 0.002 seconds. How big of a force did the ballplayer put on that ball?

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MissPhiladelphia MissPhiladelphia

25-01-2017

The change in momentum of the ball is
0.16 (44 - 38) = 0.96 kg m/s
And this should equate to the impulse delivered by a hitting force
F t = 0.96
F (0.002) = 0.96
F = 480 N

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