Answer:
Explanation:
The relation between new scale and absolute temperature scale is given as follows
Aw = 2 K
for K = 273.15 ( freezing point of water at absolute scale )
Aw = 2 x 273.15 = 546.3 K
So each division of new scale is half the each division of absolute scale
each division of new scale is small .
The value of R = 8.314 J per mole per K
Here per K is equivalent to 2Aw
So the vale of R in new scale = 8.314/2 J per mole per Aw
= 4.157 J per mole per Aw
k = R / N
= 4.157 / 6.02 x 10²³
= .69 x 10⁻²³
= 6.9 x 10⁻²⁴ J per molecule per Aw .
