The perimeter of the triangle ΔQRS formed by the midsegments of
ΔNOP is half the perimeter of ΔNOP.
Correct response:
The perimeter of ΔQRS is 8 units
How to find the perimeter of a triangle
The given parameters are;
PO = 6, PN = 4, ON = 6
According to midsegment theorem, we have;
[tex]\overline{SR} = \mathbf{\dfrac{\overline{ON}}{2}}[/tex]
[tex]\overline{RQ} = \mathbf{\dfrac{\overline{PN}}{2}}[/tex]
[tex]\overline{SQ} = \mathbf{\dfrac{\overline{PO}}{2}}[/tex]
Which gives;
[tex]\overline{SR} = \dfrac{6}{2} = \mathbf{ 3}[/tex]
[tex]\overline{RQ} = \dfrac{4}{2} = \mathbf{2}[/tex]
[tex]\overline{SQ} = \dfrac{6}{2} = \mathbf{3}[/tex]
The perimeter of ΔQRS = [tex]\overline{SR}[/tex] + [tex]\overline{RQ}[/tex] + [tex]\overline{SQ}[/tex]
Therefore;
- The perimeter of ΔQRS = 3 + 2 + 3 = 8
Learn more about the midsegment theorem here:
https://brainly.com/question/26080494
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