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A ball is kicked off of the roof of a building. The path the ball travels is modeled by the equation f(x)= -x^2 + 6x+ 16, where x is in meters. The x-axis represents the ground and the y-axis represents the building. How far from the building is the ball when it lands

Respuesta :

The ball lands 8 meters away from the building.

This question is a rather easy one which can be answered by simply solving the embedded quadratic equation.

f(x) = -[tex]x^{2}[/tex] + 6x + 16

To make our solving easier, what we do is multiply the whole equation by -1. By so doing, we make "x" positive. Then, we have

f(x) = [tex]x^{2}[/tex] - 6x - 16

Solving this equation quadratically, we have

[tex]x^{2}[/tex] + 2x - 8x - 16 = and when we factorize this expression, we have

x(x + 2) -8(x + 2) =

(x - 8) (x + 2) = 0

x - 8 = 0, x + 2 = 0

x = 8, or  x = -2

Since distance can not be in negative(minus), we then have our x to be 8 meters.

Another example on factorization can be seen here  https://brainly.com/question/13813750

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