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When a fixed amount of ideal gas goes through an isochoric process:

its temperature must increase.
its pressure must increase.
its internal (thermal) energy does not change.
no heat enters or leaves the gas.
the gas does no work.

Respuesta :

skyluke89

Answer:

the gas does no work.

Explanation:

An isochoric process is a process in which the volume of a gas is kept constant.

The work done by a gas during a transformation is given by:

[tex]W=p\Delta V[/tex]

where

p is the gas pressure

[tex]\Delta V[/tex] is the change in volume of the gas

For an isochoric process, the volume of the gas does not change, so

[tex]\Delta V[/tex]

and so, according to the previous equation, the work done by the gas is zero:

W = 0

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