Answer:
1.45 × 10⁻³ M min⁻¹
Explanation:
Step 1: Write the balanced reaction for the decomposition of dinitrogen pentoxide
2 N₂O₅(g) ⇒ 2 N₂(g) + 5 O₂(g)
Step 2: Calculate the average rate of formation of oxygen
The average rate of disappearance of N₂O₅ over the time period from t = 0 min to t = 112 min is found to be 5.80 × 10⁻⁴ M min⁻¹ (5.80 × 10⁻⁴ molN₂O₅ L⁻¹ min⁻¹). Given that the molar ratio of N₂O₅ to O₂ is 2:5, the average rate of formation of O₂ is:
5.80 × 10⁻⁴ molN₂O₅ L⁻¹ min⁻¹ × 5 molO₂/ 2 molN₂O₅ = 1.45 × 10⁻³ molO₂ L⁻¹ min⁻¹ = 1.45 × 10⁻³ M min⁻¹
