Answer:
A 140
Step-by-step explanation:
Mark the center of the circle as O. It's given that
∠IOJ = 70°
∠JOK = 70°
from the drawing it looks like HOI, IOJ and JOK are supplementary angles, which means that they add up to 180°
∠HOI + ∠IOJ + ∠JOK = 180°
∠HOI = 180° - ∠IOJ - ∠JOK
∠HOI = 180° - 70° - 70°
∠HOI = 40°
∠HOI and ∠KOL are cross angles, therefore ∠HOI = ∠KOL = 40°
Since ∠HOL and ∠KOL are supplementary angles
∠HOL = 180° - ∠KOL
∠HOL = 180° - 40°
∠HOL = 140°
