Answer:
9 pitchers
Step-by-step explanation:
Given
Cylinder 1:
[tex]Radius = r[/tex]
[tex]Height = 9[/tex]
Cylinder 2:
[tex]Radius = 3r[/tex]
[tex]Height = 9[/tex]
Required
How many pitchers' cylinder 2 can fill
First, we calculate the volume of both cylinders
Volume is calculated as:
[tex]Volume = \pi r^2h[/tex]
For A:
[tex]V_A = \pi r^2*9[/tex]
[tex]V_A = 9\pi r^2[/tex]
For B:
[tex]V_B = \pi (3r)^2 * 9[/tex]
[tex]V_B = \pi *9r^2 * 9[/tex]
[tex]V_B = 9* 9\pi r^2[/tex]
In (a): [tex]V_A = 9\pi r^2[/tex]
So, we have ve:
[tex]V_B = 9*V_A[/tex]
[tex]V_B = 9V_A[/tex]
If the first cylinder can fill 1, then the second can fill 9 pitchers
