Determine which of the following expressions are part of the greatest common factor of 54 mrt and 27 mr. Select all
situations that apply.
Plz help me

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ChoiSungHyun ChoiSungHyun · Answer 1 · 2021-01-20T07:34:09+01:00

Step-by-step explanation:

54mn⁴ = 2 * 3³ * m * n⁴

27m³n² = 3³ * m³ * n²

Highest common power of 2 = null

Highest common power of 3 = 3³

Highest common power of m = m

Highest common power of n = m²

Hence GCF(54mn⁴,27m³n²)

= 3³ * m * n² = 27mn².

27, m, n² and 9 are factors of the GCF 27mn². Only 18 is not a factor.

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manissaha129 manissaha129 · Answer 2 · 2021-01-20T07:48:42+01:00

Answer:

[tex]54m {n}^{4} = {3}^{3} \times 2 \times m \times {n}^{4} \\ 27 {m}^{3} {n}^{2} = {3}^{3} \times {m}^{3} \times {n}^{2}\\ [/tex]

GCF of the two expression 27, m, n²,9.

Both of the expression can be divided by 27, m, n², 9 but 18 can't be divided by 27m³n².

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