Answer:
[tex]\mathrm{Factor}\:2x^2-8x:\:2x\left(x-4\right)[/tex]
Step-by-step explanation:
Given the expression
[tex]2x^2-8x[/tex]
[tex]\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c[/tex]
[tex]x^2=xx[/tex]
so the expression becomes
[tex]2x^2-8x=2xx-8x[/tex]
[tex]=2xx-2\cdot \:4x[/tex]
[tex]=2x\left(x-4\right)[/tex] ∵ [tex]\mathrm{Factor\:out\:common\:term\:}2x[/tex]
Therefore,
[tex]\mathrm{Factor}\:2x^2-8x:\:2x\left(x-4\right)[/tex]
