What are the first 5 terms of the sequence if; an=2(an-1+an-2), a1=-2, a2=-3?
?
A. –3, –2, –10, –24, –68

B. –3, –2, –4, –8, –16

C. –2, –3, –10, –26, –72

D. –2, –3, –5, –8, –13

[tex]\boxed { \boxed {a_n=2(a_{n-1} + a_{n-2})}}[/tex]

[tex]a_{1} = - 2[/tex]

[tex]a_{2} = - 3[/tex]

[tex]a_{3}=2(a_{3-1} + a_{3-2}) = 2(a_{2} + a_{1}) = 2(-3 + (-2)) = -10[/tex]

[tex]a_{4}=2(a_{4-1} + a_{4-2}) = 2(a_{3} + a_{2}) = 2(-10 + (-3)) = -26[/tex]

[tex]a_{5}=2(a_{5-1} + a_{5-2}) = 2(a_{4} + a_{3}) = 2(-26 + (-10)) = -72[/tex]

Answer: –2, –3, –10, –26, –72 (Answer C)

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What are the first 5 terms of the sequence if; an=2(an-1+an-2), a1=-2, a2=-3? ? A. –3, –2, –10, –24, –68 B. –3, –2, –4, –8, –16 C. –2, –3, –10, –26, –72 D. –2, –3, –5, –8, –13

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What are the first 5 terms of the sequence if; an=2(an-1+an-2), a1=-2, a2=-3?
?
A. –3, –2, –10, –24, –68

B. –3, –2, –4, –8, –16

C. –2, –3, –10, –26, –72

D. –2, –3, –5, –8, –13