An equilateral triangular plate with sides 8 m is submerged vertically in water so that the base is even with the surface. Express the hydrostatic force against one side of the plate as an integral and evaluate it.

Respuesta :

Answer:

Hydro static force is =18377 N

Step-by-step explanation:

The hydro static force is equals to the hydro static pressure times the area.

The hydro static pressure of a fluid increases as the depth of the fluid increases and the formula of it is given below.

Hydro static Pressure, P = d·g·ρ

Where, d is the depth of the object

g is the gravitational constant

ρ is the density of the fluid

Density of water   ρ = [tex]1000 kg/m3[/tex]

=1000 kg/m^3 * 9.8m/s^2 which is √(3/2).a below the water level.

Side of the plate  x = 10 m

The hydrostatic force = the pressure at the center x the area =[tex][sqrt(3)/2 m][1000 kg/m^3 * 9.8m/s^2][/tex][tex][(1/2)(3)(8)(sqrt(3)/2) m^2][/tex]=18377 N

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