contestada

8. How much enthalpy/heat is transferred when 0.5113
gof ammonia (NH3) reacts with excess oxygen according
| to the following equation:
4NH3 +502 - 4N0+ 6H20
AH = -905.4J​

Respuesta :

First convert to moles:
0.5113 g / 17 g/mol = 0.0301 mol

Now create a ratio based on the reaction provided to solve for the unknown:

4 NH3 / -905.4 kJ = 0.0301 mol NH3 / x kJ
x = -6.808 kJ
dsdrajlin

When 0.5113 g of ammonia react with excess oxygen, -6.795 J of heat are released.

What is enthalpy?

Enthalpy, a property of a thermodynamic system, is the sum of the system's internal energy and the product of its pressure and volume.

  • Step 1. Write the thermochemical equation.

4 NH₃(g) +5 O₂(g) ⇒ 4 NO(g) + 6 H₂O   ΔH = -905.4J​

  • Step 2. Convert 0.5113 g of NH₃ to moles.

The molar mass of NH₃ is 17.03 g/mol.

0.5113 g × 1 mol/17.03 g = 0.03002 mol

  • Step 3. Calculate the heat released by the reaction of 0.03002 moles of NH₃.

According to the thermochemical equation, -905.4 J are released upon the reaction of 4 moles of ammonia.

0.03002 mol × (-905.4 J/4 mol) = -6.795 J

When 0.5113 g of ammonia react with excess oxygen, -6.795 J of heat are released.

Learn more about enthalpy here: https://brainly.com/question/11628413

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