Answer:
the answer is zero
Step-by-step explanation:
x^3 + y^3 + 12xy – 64 factorize the polynomial
x^3+y^3-4^3+3(4xy) 64 is 4^3
take x+y-4 as a common factor
(x+y-4)(x^2-xy+4x+y^2+4y+16) substitute x+y=4
(4-4)(x^2+y^2-4^2-3xy)
=0 any amount multiply by zero =0
