Answer:
For the time interval 0 to 2 the ball is in the air.
Select the options according to this.
Step-by-step explanation:
The equation should be [tex]h(t)=-16t^{2} -30t+124[/tex]
Let's find the x intercepts to answer this question.
To find x intercept where the h(t) is 0.
[tex]-16t^{2} -30t+124=0[/tex]
Solve the equation for t.
Use quadratic formula to solve the equation.
a=-16
b=-30
c=124
[tex]x=\frac{-b+/- \sqrt{b^{2}-4ac } }{2a}[/tex]
Plug in the values of a, b and c into the formula
[tex]x=\frac{30+/-\sqrt{(-30)^{2}-4(-16)(124) } }{2(-16)}[/tex]
Simplify it
[tex]x=\frac{30+/- \sqrt{900+7936} }{-32}[/tex]
[tex]x=\frac{30+/-\sqrt{8836} }{-32}[/tex]
[tex]x=\frac{30+/-94}{-32}[/tex]
Simplify it to get two values for x
[tex]x=\frac{30+94}{-32} =-3.875\\\\x=\frac{30-94}{-32} =2[/tex]
x can not be negative, here x represents time t.
So, it starts from 0 and remains in the air for 2 seconds.
