A centrifuge is used to test space pilots. The centrifuge spins with a centripetal acceleration of 3.04g. If the length of the arm of the centrifuge is 21m what is the speed of the centrifuge?

Respuesta :

Answer:

[tex]approx.= 25\frac{m}{s}[/tex]

Explanation:

Centripetal acceleration (a) is defined as the square of an object's velocity (V^2) divided by the distance of the object from it's point/axis of revolution (r). So:

[tex]a=\frac{V^{2} }{r}[/tex]

which allows us to solve for the velocity:

[tex]V=\sqrt{ar}\\ Since: a=3.04g=(3.04)(9.81),r=21;\\V=\sqrt{(3.04)(9.81)(21)} =25.02...[/tex]

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