What is the solution to In (x2 - 16) = 0?
x=1v17
x= +4
x=+/32

Answer:
x = ± [tex]\sqrt{17}[/tex]
Step-by-step explanation:
Given
ln(x² - 16) = 0, then
x² - 16 = [tex]e^{0}[/tex] = 1 ( add 16 to both sides )
x² = 17 ( take the square root of both sides )
x = ± [tex]\sqrt{17}[/tex]
Answer:
B.
Step-by-step explanation:
x²-16 = 0
Adding 16 to both sides
x² = 16
Taking square root on both sides
we get
√x² = √16
x = ± 4
Either,
x=4 OR x= -4