A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along a straight path. How fast is the tip of his shadow moving when he is 50 ft from the pole

Respuesta :

Answer:

20/3 ft/sec

Step-by-step explanation:

As given the diagram (attached),

x is the distance from the man to the pole, and y is the distance from the tip of the man's shadow to the pole.

I assume that the man and the pole are upright, meaning the 2 triangles are identical.

By similar triangles, we will get

15/y = 6/(y-x)

Triangles are similar if they have the same shape, but can be different sizes. In our case, triangles are in similar shape but in different sizes

15 (y-x) = 6y

15y-15x=6y

9y=15x

y=5/3 x

As we need to find rate of change (How fast), differentiate both sides with respect to  time t. we get

dy/dt = 5/3 dx/dt

As we have given that the man is walking from the with a speed to 4ft/s  

so dx/dt = 4, So, we need to find dy/dt (How fast the tip of shadow moving)

dy/dt = 5/3 *4

dy/dt = 20/3 or 6.666 ft/sec

In this case, the man's distance from the pole doesn't matter, because only his velocity influences how quickly his shadow goes.

Ver imagen subhashsagar
ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE