Respuesta :

Ktee10
Hello. (3x+4)(2x-1)=0 ; 6x²-3x+8x-4=0 ; 6x²+5x-4=0. What do you think?
Exvited
[tex](3x+4)(2x -1)=0 \\ \\ 3x + 4 = 0 \\ \\ 3x = -4 \\ \\ x = - \frac{4}{3} \\ \\ ---- \\ \\ 2x - 1 = 0 \\ \\ 2x = 1 \\ \\ x = \frac{1}{2} \\ \\ [/tex]

The final result is: x = -4/3 and x = 1/2.
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