Answer:
= 1227.9K
Explanation:
Given that,
D₀ = 4.0 x 10⁻⁵ m²/s,
Qd = 230,000 J/mol,
D = 6.48 x 10⁻¹⁵ m²/s
Gas constant R = 8.31 J/mol-K
T = [tex]-\frac{Q_d}{R* (InD - IND_0)}[/tex]
= [tex]-\frac{230000}{8.31* (In(6.48 * 10^-^1^5) - In(4.0 * 10^-^5)}[/tex]
= [tex]\frac{-230000}{-187.307}[/tex]
= 1227.93K
≅1227.9K
