Two students wish to determine the value of g, the acceleration due to gravity at Earth’s surface. The students have a collection of blocks of different masses, a string of negligible mass, a pulley of negligible mass, and a device for measuring acceleration. The students attach two of the blocks to the ends of the string and pass the string over the pulley so the blocks hang vertically on either side. The blocks are then released from rest, and their acceleration is measured. The students’ data for one trial are shown below, with m1 and m2 equal to the masses of the blocks. Considering the gravitational forces acting on the blocks, do the data provide a reasonable determination of the value of g, and what is a possible justification for why or why not?

Two students wish to determine the value of g the acceleration due to gravity at Earths surface The students have a collection of blocks of different masses a s class=

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Answer:

D) No, because the calculated value of g is too small, possibly due to an additional force exerted on the block-string system.

Explanation:

In order to find the value of g, we have to write the equation of the forces on the two blocks.

Since m2 is heavier than m1, this means that m2 will accelerate downward while m1 will accelerated upward, because of the tension in the rope.

For m2, we have:

[tex]m_2 g - T = m_2 a[/tex] (2)

where

[tex]m_2 g[/tex] is the weight of block m2, with

[tex]m_2 = 0.6 kg[/tex] is the mass

[tex]g[/tex] is the acceleration due to gravity

T is the tension in the rope

[tex]a=1.0 m/s^2[/tex] is the acceleration measured

For m1, we have

[tex]T-m_1 g = m_1 a[/tex] (1)

where

[tex]m_1 g[/tex] is the weight of block m1, with

[tex]m_1 = 0.4 kg[/tex] mass of m1

Re-writing T from (1) and replacing it into (2), we find

[tex]T=m_1 g + m_1 a[/tex]

[tex]m_2 g - (m_1 g + m_1 a) = m_2 a\\m_2 g - m_1 g - m_1 a = m_2 a\\g(m_2-m_1)=(m_1+m_2)a\\g=\frac{m_1 +m_2}{m_2-m_1}a=\frac{0.4+0.6}{0.6-0.4}(1.0)=5 m/s^2[/tex]

However, we know that the true value of g is [tex]9.8 m/s^2[/tex]: so the correct answer is

D) No, because the calculated value of g is too small, possibly due to an additional force exerted on the block-string system.

The data doesn't provide a reasonable determination and The possible justification is : ( D ) No, because the calculated value of g is too small, possibly due to an additional force exerted on the block-string system

Given that M₂ is heavier it will accelerate downwards while M₁ will accelerate upwards

For M₂  

M₂g - T = M₂a ---- ( 1 )

weight of Mass 2 = M₂g

T = tension on the rope

M₂ = 0.6 kg

a ( measured acceleration ) = 1.0 m/s²

For M₁

T - M₁g = M₁a  ---- ( 2 )

weight of mass 1 = M₁g

M₁ = 0.4 kg

Next step : Rewrite the value of T using both equations

T = M₁g + M₁a

M₂g - ( M₁g + M₁a ) = M₂a

∴ g ( M₂ - M₁ ) = ( M₁ + M₂ )a

Hence the value of g = [ ( 0.4 + 0.6 ) / ( 0.6 - 0.4 ) ] ( 1.0)

                                   = 5 m/s².

Since the true value of g = 9.81 m/s²  and the calculated value of g in the question is 5 m/s² which is lower than the true value.

Hence we can conclude that the possible justification is : No, because the calculated value of g is too small, possibly due to an additional force exerted on the block-string system

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