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The number of views on an interesting video after it's uploaded is represented by the following table:
Time (months)
Views
50
313
1950
12,210
76,300
10
476,800
Which model for V(t), the number of views t months after it's uploaded, best fits the data?

You might need Calculator The number of views on an interesting video after its uploaded is represented by the following table Time months Views 50 313 1950 122 class=

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Answer:

V(t)=50⋅(2.5) ^t

Step-by-step explanation:

Since the initial number of views is 50, the function that best models the number of views months after it's uploaded is V(t)=50⋅(2.5) ^t

The model V(t)=50 × [tex]2.5^{t}[/tex] represents the best approximation that fits the data.

How to form an equation?

Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.

In other words, an equation is a set of variables that are constrained through a situation or case.

If we look at the behavior of data then we can see that views are exponential increasing with time so it gives the idea that variable t should be in the power of something.

By the first data 50, it is clear that the formation should be like

V(t) = 50[tex]x^{t}[/tex] so when we put t = 0 it comes out to be 50.

Now, substitute the following data

313 = 50x²

x² = 313/50⇒ x = 2.50

Hence V(t)=50 × [tex]2.5^{t}[/tex] will be the correct model.

For more about the equation,

https://brainly.com/question/10413253

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