5. A robot that picks up tennis balls is on a straight path from (8,6) toward a ball at (-10,-5). The robot picks up a ball at (-10,-5) and then turns 90° right. What are the coordinates of appoint that the robot can move toward to pick up the last ball?

so this question is about perpendicular lines. keep in mind that a perpendicular line has a reciprocal slope of opposite sign, from the line it's perpendicular to . :) okay so what is that line the robot is on, let's first

find the slope , m

m = (y2 - y1) / ( x2 - x1)

P1 = (8,6) in the form ( x1,y1)

P2= (-10,-5) in the form (x2,y2)

then

m = (-5-6) / (-10-8)

m = -11 / -18

m = 11/ 18

and then lets use the point-slope formula with the slope we just found and one of the given points, let's pick P1

y-6 = 11/18(x-8)

y = 11/18x - 88/18 + 6

y = 11/18x -88/18 + 108/18

y = 11/18x + 20/18

now let's take the reciprocal of the slope and change the sign, then we have

y = - 18/11x +20/18 ( coordinates robot can move on )

on the graph I'm attaching the green line is the one where the robot first moves, then the purple one.. is the one it turns 90 ° on to .

5. A robot that picks up tennis balls is on a straight path from (8,6) toward a ball at (-10,-5). The robot picks up a ball at (-10,-5) and then turns 90° right. What are the coordinates of appoint that the robot can move toward to pick up the last ball?​

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5. A robot that picks up tennis balls is on a straight path from (8,6) toward a ball at (-10,-5). The robot picks up a ball at (-10,-5) and then turns 90° right. What are the coordinates of appoint that the robot can move toward to pick up the last ball?