Answer:
The co-ordinates of Q' is (5,2).
Step-by-step explanation:
Given:
Pre-image point
Q(-7,-6)
To find Image point Q' after following translation.
[tex](x,y)\rightarrow (x+12,y+8)[/tex]
Solution:
Translation rules:
Horizontal shift:
[tex](x,y)\rightarrow (x+k,y)[/tex]
when [tex]K>0[/tex] the point is translated [tex]k[/tex] units to the right.
when [tex]K<0[/tex] the point is translated [tex]k[/tex] units to the left.
Vertical shift:
[tex](x,y)\rightarrow (x,y+k)[/tex]
when [tex]K>0[/tex] the point is translated [tex]k[/tex] units up.
when [tex]K<0[/tex] the point is translated [tex]k[/tex] units down.
Given translation [tex](x,y)\rightarrow (x+12,y+8)[/tex] shows the point is shifted 12 units to the right and 8 units up.
The point Q' can be given as:
Q'=[tex](-7+12,-6+8)=(5,2)[/tex]
So, the co-ordinates of Q' is (5,2). (Answer)
