Answer:
266 m
Explanation:
We are given;
- Initial velocity, u = 12 m/s
- Final velocity, v = 26 m/s
- Time, t = 14 seconds
We are required to calculate the displacement;
- We are going to use the appropriate equation of linear motion;
- The appropriate linear motion equation is;
S = 0.5(u +v)t
Where, S is the displacement
S = 0.5(12 m/s + 26 m/s)14 seconds
= 266 m
Thus, the displacement of the train is 266 m
