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Answer:

Hi!

The correct answer is 8.

Explanation:

The combinations of bits for hosts addresses are:

.000

.001

.010

.011

.100

.101

.110

.111

The available address hosts in this case are:

  • 2³ = 8.

The general method to get the available address hosts is:

  • 2ˣ where x is the bits provided for host addresses.

Another example: For 7 bits  

2⁷ = 128

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