Answer:
True
Step-by-step explanation:
Suppose you have a quadratic function
[tex]ax ^ 2 + bx + c = 0[/tex]
Factoring this expression results in:
[tex]ax ^ 2 + bx + c = (x-h) (x-k) = 0[/tex]
Where h and k are real numbers.
Then the function is equal to 0 when [tex]x = h[/tex] and when [tex]k = 0[/tex].
Therefore h and k will always be the solutions when we have the quadratic function factored in the form
[tex](x-h)(x-k) = 0[/tex]
Since we have ensured that the factors of the function contain only real numbers, then h and k are real numbers, and x and y must also be real numbers. Therefore solutions to an equation in this form will always be real solutions.
The statement is true
