5) Point D is located in Quadrant IV. Quadrant I is where x and y are both positive. Quadrant II is where x is negative and y is positive. Quadrant III is where both x and y are negative. Quadrant IV is where x is positive and y is negative.
6) Since we know that the x will be the same because it is a vertical line segment, we just have to find the absolute value of the difference between the y of the 2 points. Therefore, (3,-8) and (3,-4) is the correct answer.
7) Use the distance formula. √((y₂-y₁)²+(x₂-x₁)²). √((8-8)²+(7-(-5))²) = √(0+12²) = √12² = 12 units.
