molality = number of mol solute/ 1000 g solvent = (2.75 mol NaOH)/1000g water
[tex] \frac{2.75( mol NaOH)}{1000(g/ water)} = \frac{x (mol NaOH)}{350(g/water)}
[/tex],
[tex]x= \frac{2.75*350}{1000} = 0.963 (mol NaOH)
[/tex][tex]0.963 (mol NaOH)* \frac{40.00 (g NaOH)}{1 ( mol NaOH)} =38.5 (g NaOH)[/tex]
