How do I find the slope of The line that passes through (0,2) and (8,8) ? Please help and please help me know how to solve it so that I can show work and show that I understand how to do it I already know the answer is 3/4 but how do I get that

[tex]General\ equation\ for\ line\ in\ slope\ intercept\ form:\\\\y=ax+b\\\\To\ find\ a\ and\ b\ substitude\ points\ (0,2),\ (8,8)\ into\ equation\\\\ \left \{ {{2=0+b}\ \ \ \ \atop {8=8a+b\ }} \right.\\\\ \left \{ {{b=2}\ \ \ \ \atop {8=8a+b\}} \right.\\\\Substitution\ method\\\\8=8a+2\\\\8a=8-2\\\\8a=6\\\\a=\frac{6}{8}=\frac{3}{4}\\\\Answer\ y=\frac{3}{4}x+2. \ Slope\ is\ a=\frac{3}{4}.[/tex]

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Lilith Lilith · Answer 2 · 2014-08-20T23:39:22+02:00

Lilith Lilith

20-08-2014

[tex](0,2) , \ \ (8,8) \\\\ ]The \ formula \ for \ the \ slope \ of \ the \ straight \ line \ going \ through \\\\ the \ points (x _{1}, y _{1})\ and \ (x _{2}, y _{2}) \ is \ given \ by: \\ \\m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} }\\\\m= \frac{ 8-2} { 8-0 } =\frac{6}{8}=\frac{3}{4}[/tex]

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