Respuesta :
Catod(-)
K⁺
2H20 +2e⁻ ---> H2 +2OH⁻
We can also say, that
K⁺ +OH⁻ +H2 = KOH +H2
At the cathode KOH and H2 are formed.
K⁺
2H20 +2e⁻ ---> H2 +2OH⁻
We can also say, that
K⁺ +OH⁻ +H2 = KOH +H2
At the cathode KOH and H2 are formed.
In the electrolysis of aqueous [tex]\rm \bold{K_2SO_4}[/tex] at the cathodic end, KOH and hydrogen gas are formed.
Electrolysis has been the process of dissociation of the compound under the influence of the electric field. The current has been passed through the sample with the help of two electrodes through the aqueous medium.
The electrodes act as the oxidation and reduction center in an electrolytic cell. The anode has been the electrode where oxidation takes place, At the cathode, reduction takes place.
Thus at the cathode in electrolysis, reduction occurs. The reduction has been the process of gain of electrons. The compound has been dissociated into potassium ions and sulfate ions in the aqueous solution.
The reduction of the potassium ion takes place at the cathode. The potassium ion along with the hydroxide ion of the aqueous solution gains electrons. The resultant would be the formation of KOH and hydrogen gas at the cathode.
The reaction can be:
[tex]\rm H_2O\;+\;2e^-\rightarrow\;H_2\;+\;OH^-[/tex]
[tex]\rm K^+\;+\;OH^-\;+H_2\;\rightarrow\;KOH\;+\;H_2[/tex]
For more information about electrolysis, refer to the link;
https://brainly.com/question/12054569
