A box that has a mass of 80 kg slides down a ramp with a 30 degree angle. The free-body diagram shows the forces acting on the box. Ignoring friction and air resistance, what is the acceleration of the box, to the nearest tenth? Answer choices are 0.5 m/s2 4.9 m/s2 8.5 m/s2 9.8 m/s2

Respuesta :

Kahtee
the first one I believe

Answer:

a= 4.9 [tex]\frac{m}{s^{2} }[/tex]

Explanation:

Force equation

[tex]F= m*a[/tex]

[tex]F= W*g*sen (30)\\F= 80 kg * 9.8 \frac{m}{s^{2} } * sen (30)\\F= 80 kg * 9.8 \frac{m}{s^{2} } * 0.5\\F= 392  *\frac{kg*m}{s^{2} } = 392[/tex] N

[tex]a= \frac{F}{m} = \frac{392 N}{80 kg} = \frac{392 \frac{kg*m}{s^{2} } }{80 kg}\\ a= 4.9 \frac{m}{s^{2} }[/tex]

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