Respuesta :

3.60 
It is a pretty simple question, I hope this helps

The required approximate value of 13 to the nearest tenth place is 3.6.

What is a recurring decimal?

Recurring Decimal is defined as also named repeating decimal, is a decimal number that only consists of repeating digits after a certain interval after the decimal. For example, 94.642642642..., 213.569569... etc.

Here,
Let x = √13
the nearest square root to the 13 is 16  of 4 and 9 of 3
So the square root of 13 lies between 9 and 16
Here, 13 is 4 more than 9 and 3 less than 16 implies a square root of 13 will be near to 4 and more than 3 and half of the difference between 4 and 3
So, for let say for small iteration
√13 = 3 -  ratio of distance + ratio of square roots of 16 to 9
√13 = 3 -  3 / 4 + 4 / 3
√13 = 3 + 0.58333333
√13 = 3 . 583333
√13 ≈ 3.6

Thus, the required approximate value of 13 to the nearest tenth place is 3.6.

For more information about recurring decimal check it out here:

brainly.com/question/820308

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