Answer:
Option C. 9
Step-by-step explanation:
To solve this question we will follow the following steps.
1).First we will arrange the data in ascending order.
8 oz, 8 oz, 12 oz, 16 oz, 16 oz, 18 oz, 20 oz, 20 oz
2).Now median of this arrangement of data will be
= [tex]\frac{16+16}{2}=16[/tex]
Median = 16
3).Now lower quartile of this sequence is 8, 8, 12, 16 and the upper quartile is 16, 18, 20, 20
4).Median of lower quatile = [tex]\frac{8+12}{2}=\frac{20}{2}=10[/tex]
5).Median of upper quartile = [tex]\frac{18+20}{2}=\frac{38}{2}=19[/tex]
6). Now we will subtract median of lower quartile from upper quartile to get the interquartile range of this list
Interquartile range = 19 - 10 = 9
Therefore Option C) 9 is the correct option.
