Write an exponential equation in the form y = abx whose graph passes through points (0, 2) and (1, 1.3)

substitute it into eq 2 and solve for a:
25 = ab^2
25 = a(10/a)^2
25 = a(100/a^2)
25 = (100/a)
a = 100/25
a = 4
.
substitute it into eq 1 and solve for b:
10 = ab
10 = 4b
10/4 = b
2.5 = b write an exponential equation y=ab^x whose graph passes through these points
(1,10), (2,25)
Hope this helps! ~Nadia~
From:(1,10)
10 = ab^1
10 = ab (equation 1)
and from:(2,25)
25 = ab^2 (equation 2)
.
solve equation 1 for b:
10 = ab
10/a = b

Answer Link

kudzordzifrancis kudzordzifrancis · Answer 2 · 2019-01-02T18:10:27+01:00

ANSWER

The required exponential equation is

[tex]y= 2{(0.65)}^{x}[/tex]

EXPLANATION

Let the equation of the exponential equation be

[tex]y = a( {b}^{x} )[/tex]

Since the graph passes through

[tex](0,2)[/tex]

it must satisfy its equation.

We substitute to obtain,

[tex]2= a( {b}^{0} )[/tex]

This simplifies to,

[tex]2= a( 1)[/tex]

This simplifies to,

[tex]a = 2[/tex]

We substitute this value into the equation to get,

[tex]y = 2( {b}^{x} )[/tex]
We apply the second point to find the value of b.

Since the graph passes through
[tex](1,1.3)[/tex]

it must also satisfy its equation.

This means that,

[tex]1.3= 2( {b}^{1} )[/tex]

This implies that,

[tex]1.3= 2b[/tex]

We divide both sides by 2 to get,

[tex]b = 0.65[/tex]

We substitute b back into the equation to get,

[tex]y= 2{(0.65)}^{x}[/tex]