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2 out of five and 2 out of five
In the bag its a ten dollar bill you have a one in five chance of getting the ten dollar bill
You have four ones in the bag you have a 4 in 5 chance of getting the one dollar bill.
Now to get 11 dollars you have a 2 in 5 chance because there is only 1 of the ten and 4 of the 1s
In the bag its a ten dollar bill you have a one in five chance of getting the ten dollar bill
You have four ones in the bag you have a 4 in 5 chance of getting the one dollar bill.
Now to get 11 dollars you have a 2 in 5 chance because there is only 1 of the ten and 4 of the 1s
The theoretical probability of getting $11 is P = 2/5, and of getting $2 the probability is P = 3/5.
How to get the probability?
Theoretically, all the bills have the same probability of being randomly drawn.
So, to get $11, we need to draw one $10 bill and one $1 bill.
The probability of getting the $10 bill is one over 5 (because there is one $10 bill and 5 bills in total).
p = 1/5.
And then we only have 4 $1 bills, so the probability of getting one of these is equal to 1.
Also, there is the case where we first draw a $1 bill, with a probability:
p = 4/5.
And then we draw the $10 one, with a probability:
P = 1/4
(now the denominator is 4, because there are 4 bills left).
The joint probability is the product of the two above
The total probability is then:
P = (1/5)*1 + (4/5)*(1/4) = 2*(1/5) = 2/5
And the probability of getting $2?
Well, en the first bill we need to get a $1 bill, the probability is:
p = 4/5
Now there are 3 $1 bills, and 4 bills in total, so the probability of drawing another $1 bill is:
q = 3/4
The joint probability is then:
P = p*q = (4/5)*(3/4) = 3/5
If you want to learn more about probability, you can read:
https://brainly.com/question/251701