Hello!
The chemical equation for the neutralization reaction between HBr and NaOH is the following:
HBr + NaOH → NaBr + H₂O
We can apply then the following equation at the equivalence point:
[tex]moles HBr=moles NaOH \\ \\ cHBr*vHBr=cNaOH*vNaOH \\ \\ vNaOH= \frac{cHBr*vHBr}{cNaOH}= \frac{0,0759M*25 mL}{0,0896 M}=21,2 mL [/tex]
So, the correct answer is 21,2 mL of NaOH
Have a nice day!
