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Arrange the steps in the correct order to solve this trigonometric equation. 2sin^2x - sin x = 0 for 0 degrees less than equal to x less than equal to 90

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Answer:

1.  2sin^2x-sinx-1=0

2. substituting sinx with u  

3. 2u^2-u-1  

4. (2u+1)(u-1)=0

5. u=1 and u=-1/2

6. replacing u with sinx so sinx=1 sinx=-1/2  

7. x=90 0  <x<90

8.x=90

Step-by-step explanation:

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