Respuesta :

[tex]b^{2}-15b-54=0. \newline b^{2}-15b=54. \newline b^{2}-15b+(\frac{15}{2})^{2}=54+(\frac{15}{2})^{2}. \newline (b-\frac{15}{2})^{2}=\frac{441}{4}. \newline b-\frac{15}{2}=\pm\frac{21}{2}. \newline b=\pm\frac{21}{2}+\frac{15}{2}. \newline b_1 = -3, b_2 = 18.[/tex]
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