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The standard form of the equation of a circle is (x−3)2+(y−1)2=16.

What is the general form of the equation?

A- x2+y2−6x−2y−26=0

B- x2+y2+6x+2y+26=0

C- x2+y2−6x−2y−6=0

D- x2+y2+6x+2y−6=0

Respuesta :

calculista
we know that
the general form of the equation of a circle is
ax² + by² + cx + dy + e = 0

we have 
(x−3)²+(y−1)²=16
x²-6x+9+y²-2y+1=16
x²+y²-6x-2y-6=0

the answer is the option
C) x2+y2−6x−2y−6=0

Answer:

x2+y2−6x−2y−6=0

Step-by-step explanation:

I took the quiz. I hope this helps :)

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