For this case, the pattern to follow is given by:
[tex] an = 3 (n-1) + 37
[/tex]
Where,
n: number of rows
an: number of total seats.
We have then that for row number 10, we must replace the value of n = 10 in the given formula.
We have then:
[tex] a10 = 3 (10-1) + 37
a10 = 27 + 37
a10 = 64
[/tex]
For the rest of the rows we repeat the procedure obtaining:
1 37
2 40
3 43
4 46
5 49
6 52
7 55
8 58
9 61
10 64
Adding the number of seats in each row we obtain:
Total = 505
Answer:
The total number of seats in the first 10 rows is:
Total = 505
